dummy PR

README.rst

@@ -52,3 +52,4 @@ the key is :code:`service_type` which has the foreign key in the
 document can only be linked to one service.
 The key :code:`service_category` table is :code:`name` of the service category
 which is then used in the :code:`services` table as foreign key.
+

otc_metadata/services.py

@@ -453,25 +453,3 @@ class Services(object):
         res.sort(key=lambda x: x.get("name", "").lower())
 
         return res
-
-    def all_services_by_cloud_environment(self, cloud_environment, environments):
-        """Retrieve all services filtered by cloud_environment
-        """
-        res = []
-        for srv in self.all_services:
-            if environments and cloud_environment:
-                for srv_cloud_environment in srv["cloud_environments"]:
-                    if srv_cloud_environment["name"] == cloud_environment:
-                        for environment in environments:
-                            if srv_cloud_environment["visibility"] == environment:
-                                res.append(srv)
-                    else:
-                        continue
-            else:
-                raise Exception("No cloud_environment or environments "
-                                "specified in function all_services_by_cloud_environment.")
-
-        # Sort services
-        res.sort(key=lambda x: x.get("service_title", "").lower())
-
-        return res